Final answer:
The function 1/g(x) is even.
Step-by-step explanation:
Given that function f is odd and function g is even, we want to determine the nature of the function 1/g(x).
An odd function has the property: f(-x) = -f(x), while an even function has the property: g(-x) = g(x).
Using these properties, let's analyze 1/g(x):
- When we substitute -x in 1/g(x), we get 1/g(-x).
- Since g(x) is even, g(-x) = g(x), so 1/g(-x) becomes 1/g(x).
- The fact that 1/g(x) = 1/g(-x) means that the function is even.
Therefore, the function 1/g(x) is even.