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Factor of 64x^4y - 36x^2y

User Mweiss
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1 Answer

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64 {x}^(4) y - 36 {x}^(2) y \\

Now take 4x^2y as common


= 4 {x}^(2) y(16 {x}^(2) - 9)

Now factorise the bracket portion using a^2 - b^2 = (a + b)(a - b) formula


= 4 {x}^(2) y( {(4x)}^(2) - {(3)}^(2) ) \\ = 4 {x}^(2) y(4x + 3)(4x - 3)

Answer:


{4x}^(2) y(4x + 3)(4x - 3)

Hope you could understand.

If you have any query, feel free to ask.

User Ravun
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