206k views
14 votes
Factor of 64x^4y - 36x^2y

User Mweiss
by
6.8k points

1 Answer

5 votes


64 {x}^(4) y - 36 {x}^(2) y \\

Now take 4x^2y as common


= 4 {x}^(2) y(16 {x}^(2) - 9)

Now factorise the bracket portion using a^2 - b^2 = (a + b)(a - b) formula


= 4 {x}^(2) y( {(4x)}^(2) - {(3)}^(2) ) \\ = 4 {x}^(2) y(4x + 3)(4x - 3)

Answer:


{4x}^(2) y(4x + 3)(4x - 3)

Hope you could understand.

If you have any query, feel free to ask.

User Ravun
by
6.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.