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what is the equation of the line that passes through (6,2) and is perpendicular to the a line with slope -1/3

User Farin
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1 Answer

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20 votes

Answer:


y = - (1)/(3) x + 4

Explanation:

point slope formula for equation of line


y - y1 = m(x - x1)

point is (6,2) slope is -1/3


y - 2 = - (1)/(3) (x - 6) \\ y - 2 = - (1)/(3) x + 2 \\ y = - (1)/(3) x + 4

User Opux
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