Answer:

Step-by-step explanation:
Exponential Function
The exponential function is often used to model natural growing or decaying processes, where the change is proportional to the actual quantity.
An exponential growing function is expressed as:

Where:
P(t) is the actual value of the function at time t
Po is the initial value of P at x=0
r is the growth rate, expressed in decimal
We need to find the model for the population of a town that grows at a rate of r = 1.2% = 0.012 each year since 1960.
We are given the population in 1960 as Po=180,000 people. Using the variable x as the number of years since 1960:

Operating:

The function to model the population of the town is:
