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If 4000J is used to move a charge through a potential difference of 0.078V, what is the charge?

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Answer:

102564.103 C

Step-by-step explanation:

From the question given above, the following data were obtained:

Energy (E) = 4000 J

Potential difference (V) = 0.078 V

Charge (Q) =?

Thus, we can obtain the charge as illustrated below:

E = ½QV

4000 = ½ × Q × 0.078

4000 = Q × 0.039

Divide both side by 4000

Q = 4000 / 0.039

Q = 102564.103 C

Thus, the charge is 102564.103 C.

User Roman Timushev
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