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Joyce pushes Efua, whose mass is 40.0 kg, with the force of 5.0 N. What is Efua's resulting acceleration?

1 Answer

4 votes

Answer:


a=0.125\ m/s^2

Step-by-step explanation:

Given that,

Mass of Efua, m = 40 kg

Force, F = 5 N

We need to find Efua's resulting acceleration. We know that the force acting on an object is given by :

F = ma

where a is acceleration


a=(F)/(m)\\\\a=(5\ N)/(40\ kg)\\\\a=0.125\ m/s^2

So, the resulting acceleration is
0.125\ m/s^2.

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