Answer:
0.2611
Explanation:
We have x to be binomially distributed random variable which denotes the items number that are defective
We have been given n = 59 as our sample size
Probability of 5% = probability of success
1-5% = 0.95
We solve using this formula
nCxP^xq^n-x
= 50C2(0.05)²(0.95)^50-2
= 0.2611
This is the probability that exactly 2 would be defective