Answer:
277 feet
Explanation:
From the information given;
The slope of the glide is said to make an angle of 3° to the ground surface;
i.e.
θ = 3°
Also, there is a plane on this glide slope whose distance is 1 mile(5280 feet) away from the touchdown.
Suppose the above expression forms and angle DEF;
where;
the distance of the plane on the glide slope to the touchdown is DF
and the height in terms of altitude is EF;
Then;
Using the tangent of the trigonometric function;
![tan \theta = (EF)/(DF)](https://img.qammunity.org/2021/formulas/mathematics/high-school/iteoolrc1sbojbh0hdycqr7vkjrbwdwa1a.png)
![tan \ 3 = (EF)/(5280)](https://img.qammunity.org/2021/formulas/mathematics/high-school/m9ubuj2fptxq51bpz2k6apg244ua097ez1.png)
EF = 5280 × tan (3°)
EF = 5280 × 0.05240777928
EF = 276.713 feet
EF ≅ 277 feet