Question

A sample of krypton gas collected at a pressure of 1.31 atm and a temperature of 26.0°C is found to occupy a volume of 23.3 liters

Answer 1

Mol of Kr gas = 1.244

Further explanation

In general, the gas equation can be written

PV=nRT

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08205 L.atm / mol K

T = temperature, Kelvin

P=1.31 atm

V=23.3 L

T=26+273=299 K

mol of sample :

`\tt n=(PV)/(RT)=(1.31* 23.3)/(0.08205* 299)=1.244`