Answer:
7.5 moles of CaBr2 are produced
Step-by-step explanation:
Based on the equation:
2AlBr3 + 3CaO → Al2O3 + 3CaBr2
2 moles of AlBr3 produce 3 moles of CaBr2 if CaO is in excess.
Using this ratio: 2 moles AlBr3 / 3 moles CaBr2. 5 moles of AlBr3 produce:
5 moles AlBr3 * (3 moles CaBr2 / 2 moles AlBr3) =
7.5 moles of CaBr2 are produced