Question

What is the acceleration due to gravity on a planet with a mass of 4.76x10^23 kg and a radius of 2,635,000 meters? Report your answer to three digits and include the units. (Ex: 7.15 m/s/s).​

Answer 1

g=4.5727 m/s^2

Step-by-step explanation:

`We\ know\ that\ , \\F=G(Mm)/(d^2) \\As\ F=ma\ and\ a=g\ (g\ is\ the\ acceleration\ caused\ due\ to\ gravity),\\mg=G(Mm)/(d^2)\\Canceling\ m\ on\ both\ sides\ we\ get,\\g=G(M)/(d^2)\\`

`We\ are\ given\ that\ ,\\Mass\ of\ the\ planet\ (M) = 4.76*10^(23) kg\\Distance(d) = 2,635,000 m\\G(Universal\ Gravitation\ Constant) = 6.67*10^(-11)\\Hence,\\g=6.67*10^(-11) ((4.76*10^(23))/(2,635,000^2) )\\g= 4.5727 m/s^2`