Answer:
To obtain a solution of 12 ml of 8% alcohol, 3 ml of 32% alcohol and 9 ml of water should be used.
Explanation:
To determine the amount of 32% alcohol and pure water needed to make a 12 ml 8% alcohol solution, the following calculation is necessary:
If in 12 ml it is sought that 8% of the solution is alcohol, this percentage implies a presence of 0.96 ml of alcohol in the solution.
Now, 12 ml of 32% alcohol has 3.84 ml of alcohol in it, which must be lowered with water to access that amount.
Therefore, since 32/8 is equal to 4, a quarter of the solution composed of 32% alcohol must be placed, while the remaining three-quarters must be pure water.
In conclusion, to obtain a solution of 12 ml of 8% alcohol, 3 ml of 32% alcohol and 9 ml of water should be used.