Question

What is the molar mass of iron (III) sulfate

Answer 1

To find how many grams of SO3 react with 3.59 mol of Fe2O3, we first calculate the needed moles of SO3 using the molar ratio from the balanced chemical equation, then convert to grams using the molar mass of SO3, resulting in 862 g of SO3.

Step-by-step explanation:

To determine how many grams of SO3 can react with 3.59 mol of Fe2O3, we follow a two-step mole-mass calculation sequence. The balanced chemical equation Fe2O3 + 3SO3 → Fe2(SO4)3 provides the molar ratio needed.

First, we calculate the number of moles of SO3 needed using the molar ratio from the chemical equation:

• 3 mol SO3 / 1 mol Fe2O3

For 3.59 mol of Fe2O3, we need:

• 3.59 mol Fe2O3 × (3 mol SO3 / 1 mol Fe2O3) = 10.77 mol SO3

Then, we convert the moles of SO3 to grams using the molar mass of SO3:

• 10.77 mol SO3 × 80.066 g/mol (the molar mass of SO3) = 862.4 g SO3

Thus, 862 g of SO3 will react with 3.59 mol of Fe2O3. This final answer is expressed to three significant figures.

Answer 2

399.88 g/mol

Step-by-step explanation:

Iron(III) sulfate, is the chemical compound with the formula Fe₂(SO₄)₃. Usually yellow, it is a salt and soluble in water. A variety of hydrates are also known. Solutions are used in dyeing as a mordant, and as a coagulant for industrial wastes.