Question

what is the molarity of an HCI solution if 25.0 ml of 0.185 M NaOH is required to neutralize 0.0200 L of HCI?​

Answer 1

Molarity of HCl solution = 0.25 M

Step-by-step explanation:

Given data:

Volume of NaOH= V₁ = 25.0 mL (25/1000 = 0.025 L)

Molarity of NaOH solution=M₁ = 0.185 M

Volume of HCl solution = V₂ = 0.0200 L

Molarity of HCl solution = M₂= ?

Solution:

M₁V₁ = M₂V₂

0.185 M ×0.025 L = M₂ × 0.0200 L

M₂ = 0.185 M ×0.025 L / 0.0200 L

M₂ = 0.005M.L /0.0200 L

M₂ = 0.25 M