Answer:
To start off, lets label this triangle ABC where A is the top right vertical, the top left verticle is B, and the bottom one is C. Now lets label the 2 points of intersection from the line segment 8x-23 D and E where the left intersection is E and the right is D.
Notice how CE and AE have an arc and that AC was split to get AE and CE. The 2 arcs show us that the intersection E is located at half the line segment.
This is the same on the other line segment BC. So if E and D are half of those line segments then the line segment ED must be half of the parallel segment above it. Because this is true, 2(8x-23)=10x+44
Now we have an equation and we can solve:
2(8x-23)=10x+44
16x-46=10x+44
6x-46=44
6x=90
x=15
Explanation: