Question

7. What initial volume of water vapor would have been present at 310 K if the volume now

is 360 cm at 541 K?
V1 =
V2=
Law:
P2=
P1=
T1=
T2=

Answer 1

206.3cm³

Step-by-step explanation:

Given parameters:

Initial temperature = 310K

Final volume = 360cm³

Final temperature = 541K

Unknown:

Initial volume = ?

Solution:

To solve this problem we apply the Charles's law which states that "the volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant".

Mathematically;

`(V_(1) )/(T_(1) )` =
`(V_(2) )/(T_(2) )`

V and T are volume and temperature

1 and 2 are initial and final states

Insert the parameters and solve for V₁;

`(V_(1) )/(310)` =
`(360)/(541)`

V₁ = 206.3cm³