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A balloon contains 3300 mL of helium gas at 63 °C. What is the final volume, in milliliters, of the gas when the temperature changes to each of the following, if pressure and amount of gas do not change? Part A 78 C Express your answer to two significant figures and include the appropriate units. UA Vi= Value Units​

User DJay
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The final volume : 3.4 L

Further explanation

Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature


\tt (V_1)/(T_1)=(V_2)/(T_2)

V₁=3300 ml

T₁=63 + 273=336 K

T₂=78+273=351 K

the final volume :


\tt V_2=(V_1.T_2)/(T_1)\\\\V_2=(3300* 351)/(336)\\\\V_2=3447.3~ml\rightarrow 2~sig.~fig.\rightarrow 3.4~L

User Antho
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