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What is the discriminant of the quadratic equation
7x^2-4x+5=0​

User Miski
by
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2 Answers

2 votes

Answer:

-124

Explanation:

The discriminant is given by

b^2 -4ac where ax^2 + bx+c =0

7x^2-4x+5=0​ so a = 7 b = -4 and c = 5

( -4) ^2 - 4(7) ( 5)

16 - 140

-124

User SaravanaRaja
by
5.6k points
5 votes

Answer:


\Delta=-124

Explanation:

The discriminant for a quadratic in standard form is given by the formula:


\Delta=b^2-4ac

We have the equation:


7x^2-4x+5=0

Hence, a=7; b=-4; and c=5.

Therefore, our discriminant will be:


\Delta=(-4)^2-4(7)(5)

Evaluate. Hence, our discriminant is:


\Delta=16-140=-124

Notes:

Since our discriminant is negative, this tells us that the quadratic has no real roots.

User Jimmij
by
6.2k points