Question

8) A block of lead has dimensions of 4.50 cm by 5.20 cm by 6.00 cm. The block weighs 1587 g. From this information, calculate the density of lead.

9) 28.5 g of iron shot is added to a graduated cylinder containing 45.50 mL of water. The water level rises to the 49.10 mL mark, from this information, calculate the density of iron.
10) What volume of silver metal will weigh exactly 2500.0 g. The density of silver is 10.5 g/cm3.

Answer 1

`11.3\ \text{g/cm}^3`

`7.92\ \text{g/cm}^3`

`238.1\ \text{cm}^3`

Step-by-step explanation:

8) Volume of lead

`V=4.5* 5.2* 6\\\Rightarrow V=140.4\ \text{cm}^3`

m = Mass of block = 1587 g

Density is given by

`\rho=(m)/(V)\\\Rightarrow \rho=(1587)/(140.4)\\\Rightarrow \rho=11.3\ \text{g/cm}^3`

Density of lead is
`11.3\ \text{g/cm}^3`

9) Volume of lead = Volume of water displaced = (49.1-45.5) = 3.6 mL =
`3.6\ \text{cm}^3`

m = Mass of iron = 28.5 g

Density is given by

`\rho=(m)/(V)\\\Rightarrow \rho=(28.5)/(3.6)\\\Rightarrow \rho=7.92\ \text{g/cm}^3`

The density of iron is
`7.92\ \text{g/cm}^3`

10) m = Mass of silver = 2500 g

`\rho` = Density of silver =
`10.5\ \text{g/cm}^3`

Volume is given by

`V=(m)/(\rho)\\\Rightarrow V=(2500)/(10.5)\\\Rightarrow V=238.1\ \text{cm}^3`

The volume of silver is
`238.1\ \text{cm}^3`