Question

A car’s brakes decelerate it at a rate of -1.60 m/s2. If the car is originally travelling at 15 m/s and comes to a stop, then how far, in meters, will the car travel during that time?

Answer 1

Using SUVAT:
S=?
U=15
V=0
A=-1.6
T= isn’t needed

V^2 = U^2 + 2AS
Rearrange for S
(V^2 - U^2) / 2A = S

(0 - 15^2) / 2(-1.6) = S
S= 225/3.2. ( Minuses cancel)

S= 70.313 3 S.F