Question

What is the vertex of the quadratic function f(x) =(x-6)(x+2)

Answer 1

Explanation:

f(x) = x^2 - 4x - 12

x = -(-4)/2 = 4/2 = 2

(2)^2 - 4(2) - 12 = 4 - 8 - 12 = -4 - 12 = -16

vertex: (2, -16)

Answer 2

(2, -16)

Step-by-step explanation: set both (x +2) and (x-6) = 0.

You get the two x-intercepts -2 and 6. Find the midpoint of the two intercepts by -2 + 6 / 2 which gives you x=2. Then plug 2 in for x and solve the original equation. ( 2 - 6)(2+2) = -16. Therefore the vertex is at (2,-16).