Question

Which two values of x are roots of the polynomial below 4x^2-6x+1

Answer 1

Explanation:

• Just apply the quadratic formula
  `x=\frac{-b \left \ {{+} \atop {-}} \right. \sqrt{b^(2)-4ac} }{2a}`

• Your equation is
  `4x^2-6x+1`
• Every quadratic equation follows the general form
  `ax^2+bx+c`

• In this case
  `a=4,b=-6,c=1`
• Substitute into the quadratic formula:
• 
  `x=\frac{-(-6) \left \ {{+} \atop {-}} \right. \sqrt{(-6)^(2)-4(4)(1)} }{2(4)}\\x=\frac{6 \left \ {{+} \atop {-}} \right. √(36-16) }{8}\\x=\frac{6 \left \ {{+} \atop {-}} \right. √(20) }{8}` Now take note that the square root of any number gives a (+) and (-) result, so two different answers
• 
  `x=(6 + √(20) )/(8) ,and\\x=(6 - √(20) )/(8)` are the answers