1 Answer

Bobthecow · Answer 1 · 2021-01-20T02:15:46+0000

Answer:

The equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3 is:

$\mathbf{y=-(2)/(3)x+1}$

Explanation:

We need to write equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3.

The equation for slope-intercept form is:
y=mx+b

where m is slope and b is y-intercept.

We are given slope m = -2/3 and we need to find y-intercept i.e b to write equation of line.

Using point (3,-1) and slope m=-2/3 we can find y-intercept i.e b

$y=mx+b\\-1=-(2)/(3)(3)+b\\-1=-2+b\\b=-1+2\\b=1$

So, y-intercept b = 1

The equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3 is:

$y=mx+b\\\mathbf{y=-(2)/(3)x+1}$

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