Question

Find three consecutive odd integers such that when the third is subtracted from five times

the sum of the first and second, the result is 798 more than the first.

Answer 1

9514 1404 393

Answer:

99, 101, 103

Explanation:

Let x represent the smallest. Then the sum of the first two is (x+x+2) and the third is x+4. The problem statement tells us the relation ...

5(2x +2) -(x +4) = x +798

10x +10 -x -4 = x +798

8x = 792

x = 99

The integers are 99, 101, 103.

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Check

5(99 +101) -103 = 99 +798

897 = 897 . . . . answer checks OK