Question

Write the equation of the line y=(5)/(6)x+(7)/(6) perpendicular to

that passes through the point (-8,7)

Answer 1

6x + 5y + 13 = 0.

Explanation:

y = 5/6x + 7/6

Gradient = 5/6

Since the line is perpendicular to y = 5/6x + 7/6

then its gradient is -6/5.

Hence its equation is: point (-8,7).

y - 7 = -6/5(x -(-8))

multiplying through by 5 we get;

5y - 35 = -6(x + 8)

5y - 35 = -6x - 48

6x + 5y + 13 = 0