Answer:
0.9 N.
Step-by-step explanation:
Mass (m) of car = 150 g
Initial velocity (u) = 0 m/s
Final velocity (v) = 24 m/s
Time (t) = 4 s
Next, we shall determine the acceleration of the car. This can be obtained as follow:
Initial velocity (u) = 0 m/s
Final velocity (v) = 24 m/s
Time (t) = 4 s
Acceleration (a) =?
v = u + at
24 = 0 + (a × 4)
24 = 0 + 4a
24 = 4a
Divide both side by 4
a = 24 /4
a = 6 m/s²
Thus, the acceleration of the car is 6 m/s²
Next, we shall convert 150 g to Kg. This can be obtained as follow:
1000 g = 1 kg
Therefore,
150 g = 150 g × 1 Kg / 1000 g
150 g = 0.15 Kg
Thus, 150 g is equivalent to 0.15 Kg
Finally, we shall determine the force of the car as follow:
Mass (m) of car = 0.15 Kg
Acceleration (a) of car = 6 m/s²
Force (F) of car =?
F = m × a
F = 0.15 × 6
F = 0.9 N
Therefore, the force of the car is 0.9 N.