Question

Solve the following system of equations algebraic
y=x^2+3x-29
y=2x-9

Answer 1

Explanation:

Given equations:

y = x² + 3x - 29 ------ (i)

y = 2x - 9 ---------------- (ii)

Now to solve this problem, we must determine the value of x and y;

Equate equations 1 and 2;

x² + 3x - 29 = 2x - 9

x² + 3x - 2x - 29 + 9 = 0

x² + x - 20 = 0

x² + 5x - 4x - 20 = 0

x(x + 5 ) - 4(x + 5) = 0

(x - 4) (x+ 5) = 0

x - 4 = 0 or x + 5 = 0

x = 4 or x = -5;

So; solve for y now;

y = 2x - 9

input x = 4 or x = -5;

y = 2(4) - 9 or y = 2(-5) - 9

y = -1 or y = -19