Question

How many moles of cesium carbonate will be produced when 5.34 moles of cesium reacts with iron (III) carbonate? (You must write and balance the formula equation!)

Answer 1

To determine the number of moles of cesium carbonate produced, a balanced chemical reaction between cesium and iron (III) carbonate is written, revealing that 5.34 moles of cesium will produce approximately 1.78 moles of cesium carbonate.

Step-by-step explanation:

The question asks about the number of moles of cesium carbonate (Cs2CO3) produced when cesium (Cs) reacts with iron (III) carbonate (Fe2(CO3)3). To solve this, we need to write and balance the chemical equation. The reaction is a single displacement where cesium displaces iron in iron (III) carbonate:

3Cs + Fe2(CO3)3 → 3Cs2CO3 + 2Fe

This balanced equation shows that 3 moles of cesium are needed to produce 3 moles of cesium carbonate and 2 moles of iron. If we have 5.34 moles of cesium reacting, it will produce (5.34 moles Cs × 1 mole Cs2CO3 / 3 moles Cs), which simplifies to approximately 1.78 moles of cesium carbonate.

Answer 2

2.67 moles of cesium carbonate (Cs2CO3).

Step-by-step explanation:

We'll begin by writing the equation for the reaction. This is illustrated below:

Cs + Fe2(CO3)3 —> Cs2CO3 + Fe

The above equation can be balance as follow:

There are 2 atoms of Fe on the left side and 1 atom on the right side. It can be balance by putting 2 in front of Fe as shown below:

Cs + Fe2(CO3)3 —> Cs2CO3 + 2Fe

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by 3 in front of Cs2CO3 as shown below:

Cs + Fe2(CO3)3 —> 3Cs2CO3 + 2Fe

There are 6 atoms of Cs on the right side and 1 atom on the left. It can be balance by putting 6 in front of Cs as shown below:

6Cs + Fe2(CO3)3 —> 3Cs2CO3 + 2Fe

Thus, the equation is balanced.

From the balanced equation above,

6 moles of Cs reacted with 1 mole of Fe2(CO3)3 to produce 3 moles of Cs2CO3.

Finally, we shall determine the moles of cesium carbonate (Cs2CO3) produced by the reaction of 5.34 moles of cesium (Cs). This can be obtained as follow:

From the balanced equation above,

6 moles of Cs reacted to produce 3 moles of Cs2CO3.

Therefore,

5.34 moles of Cs will react to produce = (5.34 × 3)/6 = 2.67 moles of Cs2CO3.

Thus, 2.67 moles of cesium carbonate (Cs2CO3) were produced from the reaction.