Answer:
B. b=3×a
a+b+c=20,000
75a+50b+40c=897,500
Explanation:
A stadium charges
$75 for each seat in section A
$50 for each seat in section B
$40 for section C.
There are three times as many seats in section B as in section A.
a = 3× b
The revenue from selling odd 20,000 seats is 897,500.
a + b + c = 20,000 seats
Hence,
$75 × a + $50 × b + $40 × c = 897,500
75a + 50b + 40c = 897,500
Hence, the system of equations is :
B. b=3×a
a+b+c=20,000
75a+50b+40c=897,500