Question

A bowl contains 28 black, 21 red, 23 blue, and 10 green balls

A ball is drawn at random. P (blue).

Answer 1

P (blue) = 23 / 82

Explanation:

There are 23 blue out of 82 (28 + 21 + 23 + 10 = 82) balls

or,

23 / 82

So, the probability of a blue ball being chosen is 23/82

(or a 28% chance [rounded])