34.5k views
25 votes
7. A man leaves ⅓of his property to his son, two fifths to his wife and the remainder to his daughter. If the daughter received sh. 24,000, what was the total amount left?​

1 Answer

10 votes

Answer:

sh 90,000

Explanation:

let x be the total amount left , then

x =
(1)/(3) x +
(2)/(5) x + 24,000

multiply through by 15 ( the LCM of 3 and 5 ) to clear the fractions

15x = 5x + 6x + 360,000

15x = 11x + 360,000 ( subtract 11x from both sides )

4x = 360,000 ( divide both sides by 4 )

x = 90,000

the total amount left was sh 90,000

User Paghillect
by
5.8k points