Question

Calculate the number of moles of solute in 431.9 L of 0.722 M sodium cyanide.

Answer 1

`312 \ mol \ solute`

General Formulas and Concepts:

Chemistry

• Molarity = moles of solute / liters of solution

Step-by-step explanation:

Step 1: Define variables

M = 0.722

L = 431.9

m = x

Step 2: Solve for x

1. Substitute:
   `0.722 \ M=(x \ mol)/(431.9 \ L)`
2. Isolate x:
   `311.832=x \ mol`
3. Rewrite:
   `x=311.832 \ mol`

Step 3: Check

Our smallest sig figs is 3. Follow sig figs rules.

`311.832 \ mol \approx 312 \ mol \ solute`