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what is the force of gravitational attraction between a 92 kg student and a 550 g slice of pizza that are 25 cm apart

User Hnnngwdlch
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1 Answer

1 vote

Answer:


F = 5.4*10^(-8)\ N

Step-by-step explanation:

Given

Represent the mass of the student with M and the mass of the slice of pizza with m


M = 92kg


m = 550g


d = 25cm

Required

Determine the force of attraction

This is calculated as:


F = (GMm)/(d^2)

Where G = gravitational constant


G = 6.67408 * 10^(-11)\ m^3 kg^(-1) s^(-2)

Convert both mass to kilogram and distance to metre


m = 550g


m = 550kg/1000


m = 0.55kg


d = 25cm


d = 25m/100


d = 0.25m

Substitute these values in
F = (GMm)/(d^2)


F = (6.67408 * 10^(-11) * 92 * 0.55)/(0.25^2)


F = (6.67408 * 92 * 0.55* 10^(-11) )/(0.25^2)


F = (337.708448* 10^(-11) )/(0.0625)


F = 5403.335168* 10^(-11)


F = 5.403335168* 10^3*10^(-11)


F = 5.403335168*10^(3-11)


F = 5.403335168*10^(-8)


F = 5.4*10^(-8)\ N

User Doza
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