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31 votes
31 votes
What is the slope of a line perpendicular to the line whose equation is 2x+3y=21. Fully simplify your answer.

User Norbitrial
by
3.4k points

2 Answers

6 votes
6 votes

Answer:

2x+3y=21.

the answer is
(3)/(2)

simplify the answer I think. x = 2 + y = 3 = 21

x = 2
x + 1 = 3

y = 3

y - 1

2 + 1 = 3

3 - 1 = 2

The answer will only be
(3)/(2) no y =
(3)/(2) just
(3)/(2)

Don't forget to look at the picture

What is the slope of a line perpendicular to the line whose equation is 2x+3y=21. Fully-example-1
User Dcool
by
3.4k points
21 votes
21 votes

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above


2x+3y=21\implies 3y=-2x+21\implies y=\cfrac{-2x+21}{3} \\\\\\ y=\cfrac{-2x}{3}+\cfrac{21}{3}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+7\qquad \impliedby \begin{array} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

therefore then


\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-2}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-2}\implies \cfrac{3}{2}}}

User Pradeep SJ
by
2.8k points
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