What methods could be used to solve the following quadratic equation x^2 +12-28=0

asked Jan 11, 2021 202k views

4 votes

by Jacg

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Answer:

Explanation:

x^2 +12x-28=0

x^2+(14-2)x-28=0

x^2+14x-2x-28=0

X(X+14)-2(X+14)=0

(X+14)(X-2) is the factor of this quadratic equation.

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