Question

Nitrogen gas at 300 k and 200 kpa is throttled adiabatically to a pressure of 100 kpa if the change in kinetic energy is negligble the temperature of the nitrogen after throttling will be:_________

Answer 1

The temperature of the Nitrogen after throttling is
`T_2 = 300 \ K`

Step-by-step explanation:

From the question we are told that

The temperature is
`T_1 = 300 \ K`

The pressure is
`P = 200 \ kPa = 200 * 10^(3) \ Pa`

The pressure after being
`P_1 = 100 \ kPa = 100 * 10^(3) \ Pa`

Generally from the first law of thermodynamics we have that

`Q - W = \Delta U + \Delta K`

Here
`\Delta U` is the change internal energy which is mathematically represented as

`\Delta U = C_p (T_2 - T_1)`

Here
`C_p` is the specific heat of the gas at constant pressure

`\Delta K` is the change kinetic energy which is negligible

Q is the thermal energy which is Zero for an adiabatic process

W is the work done and the value is zero given that the gas was throttled adiabatically

So

`0= \Delta U +0`

=>
`\Delta U = 0`

=>
`(T_2 - 300) = 0`

=>
`T_2 = 300 \ K`