Question

You are at a circus and you see a stunt man climb up 29.4 meters into a cannon. He gets fired horizontally out of the cannon with a speed of 57.1 m/s. How long was stunt man in the air for?

Answer 1

t = 2.44 s

Step-by-step explanation:

Given that,

A stunt man climb up 29.4 meters into a cannon. He gets fired horizontally out of the cannon with a speed of 57.1 m/s.

We need to find the time for which was the stunt man in the air. Let it is t. It can be calculated using second equation of motion as follows :

`s=ut+(1)/(2)gt^2`

u is initial speed and it is 0

`s=(1)/(2)gt^2\\\\t=\sqrt{(2s)/(g)} \\\\t=\sqrt{(2* 29.4)/(9.8)} \\\\t=2.44\ s`

So, the stunt man is in the air for 2.44 seconds.