Question

What survival rate in the 10th year would make the average

rate of loss over the 10-year period equal to 38.0%?

Answer 1

The answer is "63%"

Explanation:

please find the complete question in the attached file.

Time= 10 year =38.0%

let,

x=rate

`\to 38 = ((36.2 + 29.0 + 46.2 + 37.5 + 40.9 + 40.0 + 32.6 + 40.5 + 40.1 + x))/(10)`

`\to 38 = ((343 + x ))/(10)\\\\\to 380 = (343 + x )\\\\\to 380 - 343 = x \\\\\to x= 37\%`

The rate of survival differs from the rate of loss, meaning the rate of survival were:

`= 1 - loss\ rate \\\\= 1 - 37\% \\\\= 1 - (37)/(100) \\\\= (100-37)/(100) \\\\= (63)/(100) \\\\=63 \%`