219,976 views
43 votes
43 votes
A 500 Kg load is lifted through a vertical height of 10m in 25s by a crane. Calculate the power of the crane

User Mirek
by
2.8k points

1 Answer

15 votes
15 votes

Answer:

1962 W

Step-by-step explanation:

P = W/t

P = F d cos theta / t

P = (500 kg) (9.81 m/s^2) (10 m) (cos 180) / 25 s <-- the displacement and the force act in opposite directions (but it doesn't matter because direction doesn't matter in this case)

P = 1962 W

User Mark Anderson
by
2.8k points