373,123 views
27 votes
27 votes
A motor car tyre contained a fixed mass of air at 27 °C. Its pressure was 220 kN m2 above atmospheric pressure. After a 60-minute drive, the air pressure rose to 250 ken m-² above atmospheric pressure. What was the new pressure of the air in the tyre, in degrees Celsius, if the volume of air remained constant? [Atmospheric pressure = 200 k N m-²] The general gas equation is P1V1 = P2V2 T1 T2​

User Mohit Kumar
by
3.7k points

1 Answer

20 votes
20 votes

Answer:

in this situation we have given a car note engine whose efficiency is 40%. Now it is told that it is desired to have an efficiency of 60%. Then we have to find the thing temperature force him intact temperature as we know that efficiency is given by that is neat is equal to this is one minus the lower temperature upon t higher temperature here lower temperature is the temperature of think and higher temperature is the temperature of source. So we can say that in the first case we are given the efficiency that is 40%. So this is 4100 is equal to, this is one minus deal upon, this is 500 From here we can find the value of lower 10%. This will comes out to be 300 Calvin. No, we have given that the efficiencies 60%. So we can the lower temperature remains him that is 300 Calvin. And we have to find the higher temperature. So we can say that this is 60 upon 100 is equal to this is one minus 300 upon th from here we can find the value of higher temperatures. So this is 300 upon th is equal to disease 40 by 100. Or we can say yes, you'll come out to be 7 50 Calvin. So this is the temperature and this is our answer for this. Given to shin. So we can say for that option, B is the correct choice. Thank you

Step-by-step explanation:

User StuS
by
3.0k points