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What is the asymptote of g(x)= 4 (1/3) - 2

User Lungj
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1 Answer

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Answer: X=2

Explanation:

Assuming the function is

All logarithmic functions, despite their base, has a vertical asymptote at argument = 0.

That is not changed by the vertical stretching made by the 4 which multiplies the logarithm nor the vertical shift made by the +5.

In this case the argument is x - 2, then the vertical asymptote is:

x - 2 = 0

User Ritwik
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