Question

If the escalator pulls you up a slope of 30.0o​ ​ and moves with a velocity of 3.10m/s. What is the vertical component of your velocity? What is the horizontal component of your velocity?

Answer 1

`1.55\ \text{m/s}`

`2.68\ \text{m/s}`

Step-by-step explanation:

v = Velocity of the elevator = 3.1 m/s

`\theta` = Angle of the slope =
`30^(\circ)`

Vertical component is given by

`v_y=v\sin\theta\\\Rightarrow v_y=3.1\sin30^(\circ)\\\Rightarrow v_y=1.55\ \text{m/s}`

The vertical component of the velocity is
`1.55\ \text{m/s}`.

Horizontal component is given by

`v_x=v\cos\theta\\\Rightarrow v_x=3.1* \cos30^(\circ)\\\Rightarrow v_x=2.68\ \text{m/s}`

The horizontal component of the velocity is
`2.68\ \text{m/s}`.