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Balance the Following Equations: SiCl4 + H2O = SiO2 + HCl A) 1 SiCl4 + 1 H2O = 2 SiO2+ 4 HCl B) 2 SiCl4 + 2 H2O = 1 SiO2+ 4 HCl C) 2 SiCl4 + 1 H2O = 1 SiO2+ 4 HCl D) 1 SiCl4 + 2 H2O = 1 SiO2+ 4 HCl
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Balance the Following Equations: SiCl4 + H2O = SiO2 + HCl

A) 1 SiCl4 + 1 H2O = 2 SiO2+ 4 HCl

B) 2 SiCl4 + 2 H2O = 1 SiO2+ 4 HCl

C) 2 SiCl4 + 1 H2O = 1 SiO2+ 4 HCl

D) 1 SiCl4 + 2 H2O = 1 SiO2+ 4 HCl

User Quintin B
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The answer would be D.

SiCl4 + 2H2O → SiO2 + 4HCl (balanced equation)
User Eoin
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