Question

A quantum of light has frequency of 1.8 x 10^14 Hz. Finds its energy.

Answer 1

Its energy : 1.193 x 10⁻¹⁹ J

Further explanation

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

`\large{\boxed{\bold{E\:=\:h\:.\:f}}}`

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

f = c / λ

c = speed of light

= 3.10⁸

λ = wavelength

`\tt E=6.626* 10^(-34)* 1.8* 10^(14)\\\\E=1.193* 10^(-19)~J`