Question

A paintball is fired horizontally from a tower 45 m above the ground. If the paintball gun fires at 90 m/s… How long does it take for the paintball to hit the ground? How far away from the tower will the paintball land?

Answer 1

The time taken for the paint ball to hit the ground is
`t = 2.143 \ s`

The distance of the landing point from the tower is
`d = 192.86 \ m`

Step-by-step explanation:

From the question we are told that

The height of the tower is
`h = 45 \ m`

The speed of the paintball in the horizontal direction is
`v_x = 90 \ m/s`

Generally from kinematic equation we have that

`h = ut + (1)/(2) at^2`

Here u is the initial velocity of the paintball in the vertical direction and the value is 0 m/s , this because the ball was fired horizontally

a is equivalent to
`g = 9.8\ m/s^2`

t is the time taken for the paintball to hit the ground

So

`45 = 0* t + (1)/(2) 9.8 * t^2`

=>
`t = 2.143 \ s`

Generally the distance of its landing position from the tower is

`d = v * t`

=>
`d = 90 * 2.143`

=>
`d = 192.86 \ m`