Question

Find the 9th term of the geometric sequence 8,32,128,

Answer 1

`\text{First term,}~ a = 8\\\\\text{Common ratio,}~ r= \frac{32}8 = 4\\\\\text{nth term} = ar^(n-1) \\\\\text{9th term} = 8\cdot 4^(9-1)\\\\\\~~~~~~~~~~~~~=8 \cdot 4^8\\\\\\~~~~~~~~~~~~~=524288\\\\\text{The 9th of the geometric sequence is 525288.}`