Answer:
![x = (54)/(59)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ehpf0vfjv8fedmy7dfa3r8k8m2pnhzsjhn.png)
Explanation:
I'm assuming you meant (83x - 6). Either way, the parentheses aren't needed there as there aren't any numbers outside of the parentheses on that side of the equation.
So:
Remember PEMDAS
P – Parentheses
E – Exponents
M – Multiplication /D – Division (whichever comes first from left to right)
A – Addition /S – Subtraction (whichever comes first from left to right)
Nothing needs to be distributed on the left side, so let's distribute the right side.
6(4x + 8)
6 * 4x = 24x
6 * 8 = 48
Now we have 24x + 48
83x - 6 = 24x + 48
Now, we must isolate the x so that in the end, we can get x =
83x - 6 = 24x + 48
+ 6 +6
83x = 24x + 54
-24x -24x
59x = 54
Now, we have isolated the x! Finally, we want x to = 1 so that it will be x = instead of 59x =.
![(59x)/(59) = (54)/(59)](https://img.qammunity.org/2021/formulas/mathematics/high-school/hi0df7vh6rmrfrsxdy7mq85h2occjj5edl.png)
Because 54/59 does not divide into a rational number or simplify any further, we can keep it as a fraction.
![x = (54)/(59)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ehpf0vfjv8fedmy7dfa3r8k8m2pnhzsjhn.png)
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