Question

Convert 6.7 x 1024 molecules of nitrogen dioxide into grams.

Answer 1

510 g NO₂

General Formulas and Concepts:

• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
• Reading the Periodic Table
• Writing Compounds
• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

6.7 × 10²⁴ molecules NO₂ (Nitrogen dioxide)

Step 2: Define conversions

Avogadro's Number

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of NO₂ - 14.01 + 2(16.00) = 46.01 g/mol

Step 3: Use Dimensional Analysis

`6.7 \cdot 10^(24) \ molecules \ NO_2((1 \ mol \ NO_2)/(6.022 \cdot 10^(23) \ molecules \ NO_2) )((46.01 \ g \ NO_2)/(1 \ mol \ NO_2) )` = 511.901 g NO₂

Step 4: Check

We are given 2 sig figs. Follow sig fig rules.

511.901 g NO₂ ≈ 510 g NO₂