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What is the highest order dark fringe, , that is found in the diffraction pattern for light that has a wavelength of 575 nm and is incident on a single slit that is 1410 nm wide?

User SciPhi
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1 vote

Answer:

The highest order dark fringe is 2

Step-by-step explanation:

From the question we are told that

The wavelength is
\lambda = 575 \ nm = 575 *10^(-9) \ m

The width is of the slit is
d = 1410 nm = 1410 *10^(-9) \ m

Generally the highest order dark fringe is mathematically represented as


m = (w)/(\lambda )

=>
m = ( 1410 *10^(-9))/( 575 *10^(-9) )

=>
m =2

User Vdrmrt
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