Question

27x9^3x can be written in the form 3^k where K is an expression in terms of x. Find k

Answer 1

k = 3 + 6x

Explanation:

Using the rule of exponents

`a^(m)` ×
`a^(n)` ⇔
`a^((m+n))`

`(a^(m)) ^(n)` =
`a^(mn)`

Given

27 ×
`9^(3x)`

= 3³ ×
`(3^(2)) ^(3x)`

= 3³ ×
`3^(6x)`

=
`3^(3+6x)`

=
`3^(k)` → with k = 3 + 6x